t^2+87t+1892.25=117.51

Solution for t^2+87t+1892.25=117.51 equation:

t^2+87t+1892.25=117.51

We move all terms to the left:

t^2+87t+1892.25-(117.51)=0

We add all the numbers together, and all the variables

t^2+87t+1774.74=0

a = 1; b = 87; c = +1774.74;
Δ = b2-4ac
Δ = 872-4·1·1774.74
Δ = 470.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(87)-\sqrt{470.04}}{2*1}=\frac{-87-\sqrt{470.04}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(87)+\sqrt{470.04}}{2*1}=\frac{-87+\sqrt{470.04}}{2}
$